2u^2+4=96

Solution for 2u^2+4=96 equation:

2u^2+4=96

We move all terms to the left:

2u^2+4-(96)=0

We add all the numbers together, and all the variables

2u^2-92=0

a = 2; b = 0; c = -92;
Δ = b2-4ac
Δ = 02-4·2·(-92)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{46}}{2*2}=\frac{0-4\sqrt{46}}{4}
=-\frac{4\sqrt{46}}{4}
=-\sqrt{46}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{46}}{2*2}=\frac{0+4\sqrt{46}}{4}
=\frac{4\sqrt{46}}{4}
=\sqrt{46}
$